Linear algebra: determinants (proof)

yoda05378
Messages
11
Reaction score
0
hi, i seem to have some trouble proving:

Suppose M = [A B:O C], where A is a kxk matrix, C is a pxp matrix, and O is a zero matrix. Show that det(M) = det(A)det(C).


my attempt at a proof:

det(M) = det(A)det(C)

det[A B:O C] = det(A)det(C)

AC - OB = det(A)det(C)

AC = det(A)det(C) <-- doesn't make sense!

please point out where my logic failed.
 
Physics news on Phys.org
nevermind. i figured out where i went wrong (i treated the matrices as if they were scalar, stupid me). thanks for all the help :sarcasm:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top