Linear Algebra: Distance problems.

haux
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Homework Statement



Let P=(5,5,−1), Q=(6,7,2), R=(7,6,0) and S=(7,3,−2). Let l1 be the line passing through P and Q, and let l2 be the line passing through R and S.

(i) The distance between R and l1 is _____

(ii) The distance between l1 and l2 is _____

Homework Equations


projd(v) =
[(v • d)] d
[||d||2]

The Attempt at a Solution



1. Since it said l1 was represented by points PQ and l2 by points RS, I took Q-P and S-R which resulted in:

l1 = (6,7,2)-(5,5,-1) =(1,2,3)
l2 = (7,3,-2)-(7,6,0) = (0,-3,-2)

Now that we have two lines represented by three points, for the first part of the question, can we use the projection formula for 'R'? Also, even though l1 and l2 are now represented by three points, are we supposed to combine all the original points somewhere down the road to create an equation of the line? Thanks.
 
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Hi haux! :smile:
haux said:
Let P=(5,5,−1), Q=(6,7,2), R=(7,6,0) and S=(7,3,−2). Let l1 be the line passing through P and Q, and let l2 be the line passing through R and S.

(i) The distance between R and l1 is _____

1. Since it said l1 was represented by points PQ and l2 by points RS, I took Q-P and S-R which resulted in:

l1 = (6,7,2)-(5,5,-1) =(1,2,3) …

Hint: you'll also need either RP or RQ :wink:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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