Linear Algebra orthogonality problem

mpittma1
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Homework Statement


Let W be the intersection of the two planes

x + y + z = 0 and x - y + z = 0

In R3. Find an equation for Wτ


Homework Equations





The Attempt at a Solution



So, W = {(x, y, z) l 2y =0}

I don't think that is a correct was to represent W being the intersection of the planes though.

I can find Wτ after I know how to find my equation for W.

Any thoughts for how to find the equation for W?
 
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mpittma1 said:

Homework Statement


Let W be the intersection of the two planes

x + y + z = 0 and x - y + z = 0

In R3. Find an equation for Wτ


Homework Equations





The Attempt at a Solution



So, W = {(x, y, z) l 2y =0}

I don't think that is a correct was to represent W being the intersection of the planes though.

I can find Wτ after I know how to find my equation for W.

Any thoughts for how to find the equation for W?

##y=0## alright, but you need more. You also need ##x=-z## for ##(x,y,z)## to be on both planes. Do you see how to write the equation from that?
 
LCKurtz said:
##y=0## alright, but you need more. You also need ##x=-z## for ##(x,y,z)## to be on both planes. Do you see how to write the equation from that?

Im not seeing how to get x = -z...
 
mpittma1 said:
Im not seeing how to get x = -z...

Look at the equations of the two planes when ##y=0##.
 
LCKurtz said:
Look at the equations of the two planes when ##y=0##.

Ok so you "Let" x = -z, so that way when y=0 the equation for the two planes become x + z = 0

so x has to be equal to - z to make -z + z = 0 right?
 
Yes. So what is the equation of the line of intersection?
 
x+z = 0?
 
No. That is the equation of a plane in 3D. You might look, for example, here:

http://www.math.hmc.edu/calculus/tutorials/linesplanesvectors/
 
A tip is to see x=-z as (x-0)/1 = (z-0)/-1.
 
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