Proving Consistency in Linear Systems: The Case of Three Equations

In summary, for the system of equations with variables x, y, and z to have at least one solution, the values of a, b, and c must satisfy the equation c = a + b. This can be proven by setting up the matrix system and showing that the rank of the coefficient matrix must equal the rank of the augmented matrix in order for the system to have a solution. This can be achieved by getting the matrix to row-echelon form.
  • #1
CaityAnn
38
0
I have three systems of equations:
x+y+2z=a , x+z= b and 2x+y+3z=c
Show that in order for this system to have at least one solution, a,b,c must satisfy c=a+b.

Obviously I can add the equations a and b and get c. But I don't know how else to approach showing this. I think the points of x,y,z of c must satisfy both a,b and provide a solution set for both but I am not sure how to prove that. HELP PLEASE~!
 
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  • #2
The matrix system is:

[tex] \begin{bmatrix}
1 & 1 & 2 & a \\
1 & 0 & 1 & b \\
2 & 1 & 3 & c \\
\end{bmatrix}[/tex]

The system has at least one solution if the rank of the coefficient matrix equals the rank of the augmented matrix. Get the matrix to row-echleon form.
 
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