Linear approximation given accuracy points

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SUMMARY

The discussion focuses on verifying the linear approximation of the function tan(x) at a = 0, represented as tan(x) ≈ x. The derivative of tan(x) is established as sec^2(x), leading to the linear function L(x) = x. Participants are tasked with determining the values of x for which this approximation holds true within an accuracy of 0.1, specifically within the interval -1 ≤ x ≤ 1. Suggestions include using a graphing calculator to visualize the functions and creating a table to identify the x-values where the approximation diverges from the actual function.

PREREQUISITES
  • Understanding of linear approximations in calculus
  • Familiarity with derivatives, specifically sec^2(x)
  • Proficiency in using graphing calculators or graphing software
  • Basic knowledge of function behavior in the interval -1 ≤ x ≤ 1
NEXT STEPS
  • Learn how to use a graphing calculator to plot functions
  • Study the concept of Taylor series for better approximation techniques
  • Explore error analysis in numerical methods
  • Investigate the behavior of trigonometric functions near their linear approximations
USEFUL FOR

Students studying calculus, educators teaching linear approximations, and anyone interested in the practical applications of derivatives in function analysis.

Hemolymph
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Homework Statement



Use a graphing calculator or computer to verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to within 0.1. (Round the answers to two decimal places.)
tan(x) ≈ x

Homework Equations



derivative of tan(x) = sec^2(x)

The Attempt at a Solution



f(0)= tan(0)=0
fprime(0)= sec^2(0)= 1
L(x)=f(a)+fprime(a)(x-a)
L(x)=0+1(x-0)
L(x)=x

not sure how to continue from here
 
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Hemolymph said:

Homework Statement



Use a graphing calculator or computer to verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to within 0.1. (Round the answers to two decimal places.)
tan(x) ≈ x

Homework Equations



derivative of tan(x) = sec^2(x)

The Attempt at a Solution



f(0)= tan(0)=0
fprime(0)= sec^2(0)= 1
L(x)=f(a)+fprime(a)(x-a)
L(x)=0+1(x-0)
L(x)=x

not sure how to continue from here
I don't think you need to derive the result.

Graph y=tan(x) and y=x for -1 ≤ x ≤ 1 or some similar interval near zero.

Make a table of x and tan(x) for some values starting at x=0, and continuing until you have a difference of 0.1.
 

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