Linear Approximation of Tanx at a=0: Determining Accuracy Within 0.1

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Homework Statement


Verify the linear approximation tanx = x at a=0.
Then determine the values of x for which the linear approximation is accurate to within 0.1.


Homework Equations


L(x)=f(a) + f'(a) (x-a)


The Attempt at a Solution


Besides writing down that tanx - 0.1 < x < tanx + 0.1
I have no idea how to approach this!
 
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If you want an 'exact' answer (to some number of signficant digits) to that inequality you would have to solve it numerically. I suspect they want you to estimate a remainder term to the Taylor series. What forms of that do you know?
 
I don't know what the Taylor series is. I don't think they're looking for a numerical answer though. I think they're looking for some sort of proof? I just started learning linear approximations.
 
If you don't know what a Taylor series is, forget that suggestion. Just goof around with your calculator to figure out how big x can be and still keep |x-tan(x)|<0.1. There's not really a nice way to do it.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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