A9876
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Homework Statement
1. A particular solution \Psin(x,t) of the TDSE, -iℏ∂\Psi/∂t=\hat{H}\Psi, can be constructed by taking \Psin(x,t)=ψn(x)exp(-iEnt/ℏ) where the ψn are solutions of the TISE.
a) Show that a linear combination of 2 such solutions c1\Psi1(x,t) + c2\Psi2(x,t) is also a solution of the TDSE but not a solution of the TISE.
b) Consider a Hamiltonian \hat{H} with eigenvectors \phi1 and \phi-1 and corresponding energy eigenvalues E1=ℏω and E-1=-ℏω. If at time t=0, the state of the system is \Psi(t=0)=c1\phi1(t=0)+c-1\phi-1(t=0), give the state of the system at an arbitrary later time t. This system demonstrates recurrences, where \Psi(t)=\Psi(0). At what time will this occur?
c) What's the expectation value of the energy \langleE\rangle at an arbitrary later time t for the case c1=c-1.
d) Consider now the 2 (also orthonormal) quantum states: v±(t)=(\phi1(t)±\phi-1(t))/√2. Find \phi1(t) and \phi-1(t) in terms of the v±(t)
e) If at time t=0, the state of the system is found to be ψ(0)=v-, find the probability as a function of time, that ψ(t) will be found in the state v+
Homework Equations
The Attempt at a Solution
a) Not sure if this is right
\Psi(x,t)=c1ψ1(x)exp(-iE1t/ℏ)+c2ψ2(x)exp(-iE2t/ℏ)
|\Psi(x,t)|2= |c1|2|ψ1|2+|c2|2|ψ2|2+c1*c2ψ1*ψ2exp(-i(E2-E1)t/ℏ)+c1c2*ψ1ψ2*exp(-i(E1-E2)t/ℏ)
Not a stationary state since |\Psi(x,t)|2≠ |\Psi(x,t=0)|2 ∴ solution of TDSE but not of TISE
b) Not sure how to finish the question
\Psi(x,t)=c1\phi1(x)exp(-iE1t/ℏ)+c-1\phi-1(x)exp(-iE-1t/ℏ)
=c1\phi1(x)exp(-iωt)+c-1\phi-1(x)exp(iωt)