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Linear Differential Equation - Initial Value Problem

  1. Nov 7, 2015 #1
    Hello, I'm struggling with a simple problem here.

    It asks me to solve the following initial value problem:
    fSfRWNn.png

    So far I've calculated the integration factor μ(x) = ex-x2 and I multiplied both sides of the equation by it and got this:
    http://www4c.wolframalpha.com/Calculate/MSP/MSP36171f59839bdf0g6cbd000044defig6e40h0ei0?MSPStoreType=image/gif&s=64&w=256.&h=47. [Broken]

    The problem I'm having is that the equation I got is different than the equation in the first line of the solution:
    2zu70dx.png

    I don't understand how the ex-x2⋅(1 - 2x)⋅y disappeared


    EDIT: Actually, nevermind. My brain was too lazy to realize that the left part of the equation is equal to the derivative of ex-x2⋅y so I could just simplify it
     
    Last edited by a moderator: May 7, 2017
  2. jcsd
  3. Nov 7, 2015 #2

    Simon Bridge

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    Well done.
     
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