Linear Independence of Vectors Spanning $\mathbb{R}^n$

Dustinsfl
Messages
2,217
Reaction score
5
If x1, x2,..., xn span \mathbb{R}^n, then they are linearly independent.

This is true since n-1 vectors can't span R^n.

How can this be written in a more meaningful way?
 
Physics news on Phys.org
\mathbb{R}^n is an n-dimensional vector space. {x1,x2,...,xn} is a spanning set of \mathbb{R}^n of length n. This makes {x1,x2,...,xn} a basis of \mathbb{R}^n, which means it must be linearly independent.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top