Linear Motion: 0.525kg Ball Travels 200m in 10s

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Homework Help Overview

The problem involves a 0.525kg ball that starts from rest and rolls down a hill with uniform acceleration, specifically focusing on the distance it travels during the second 10 seconds of its motion, which is stated to be 200m.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the meaning of "during the second 10.0 s of its motion" and whether it implies a typo. There are attempts to clarify the problem's requirements, including questions about calculating acceleration and the distance traveled at different time intervals.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some have proposed equations to find acceleration and distance, while others express confusion about the setup and calculations. There is no explicit consensus on the correct approach yet.

Contextual Notes

Participants note potential issues with unit correctness and the interpretation of time intervals in the problem statement. There is also a mention of conflicting distance calculations, indicating uncertainty in the problem's parameters.

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Homework Statement



A 0.525kg ball starts from rest and rolls down a hill with uniform acceleration, traveling 200m during the second 10.0 s of its motion.

Homework Equations



xf= xi + vi +1/2a(t)^2
x= vi + at

The Attempt at a Solution



a= 4 m/s^2

x=50 mits wrong
 
Last edited:
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A 0.525kg ball starts from rest and rolls down a hill with uniform acceleration, traveling 200m during the second 10.0 \rm s of its motion.

So, are you trying to solve for acceleration?
what does this part mean, "during the second 10.0 \rm s of its motion" is it a typo?
 
solve the distance it travels @ 5 seconds.
 
So the question states that the ball travels during the second 10s and you are trying to find the distance after the first 5 seconds?

Use a = 2d / t² to find acceleration where t will be your 10 seconds
Then use the equation d = ut + ½ at² where t will be your 5 seconds and solve for distance...

I also got x = 50... are your units correct?

Edit:
Maybe it is 16.63 m? (edited again)
a=200m/150 s² = 1.33m/s²
d = ut + ½ at²
d = 0 + ½ (1.33)(5)²
 
Last edited:
hmmmmmm I am so confused
 

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