Linear System - Network Flow Matrices

1LastTry
Messages
63
Reaction score
0

Homework Statement


Consider the network of streets with intersections a,b,c,d and e below. The arrows indicate the direction of traffic flow along the oneway streets, and the numbers refer to the exact number of cars observed to enter or leave a,b,c,d and e during one minute. Each xi denotes the unknown number of cars which passed along the indicated streets during the same period.
See Attached Image
Linear System:
x1+x6-x5=55
x5-x4=35
x6+x3-x4=60
x3-x2=40
x1-x2=70

Reduced row-echelon form
1 0 0 0 -1 1 | 55
0 1 0 0 -1 1 |-15
0 0 1 0 -1 1 |25
0 0 0 1 -1 0 |-35
0 0 0 0 0 0 |0
s t
General Solution:
x1=55+s-t
x2=-15+s-t
x3=25+s-t
x4=-35-s
x5=s
x6=t

The question is: if ED were closed due to roadwork, find the minimum flow along AC, using your results in the general solution.
Note: x2 = ED therefor x2=0, and AC is x6

Homework Equations





The Attempt at a Solution



I know x2=0 and no idea what to do with S and T...
what I did is set x2=0 so -15+s-t=0 so S=t+15
And sub it into the general solution you get:
x1=70
x2=0
x3=40
x4=-20+t
x5=15+t
x6=t

so x4≥0 when t≥20
x6≥0 when t≥0
So minflow is 0?
 

Attachments

  • IMG_0238.jpg
    IMG_0238.jpg
    29.3 KB · Views: 496
Physics news on Phys.org
1LastTry said:

Homework Statement


Consider the network of streets with intersections a,b,c,d and e below. The arrows indicate the direction of traffic flow along the oneway streets, and the numbers refer to the exact number of cars observed to enter or leave a,b,c,d and e during one minute. Each xi denotes the unknown number of cars which passed along the indicated streets during the same period.
See Attached Image
Linear System:
x1+x6-x5=55
x5-x4=35
x6+x3-x4=60
x3-x2=40
x1-x2=70

Reduced row-echelon form
1 0 0 0 -1 1 | 55
0 1 0 0 -1 1 |-15
0 0 1 0 -1 1 |25
0 0 0 1 -1 0 |-35
0 0 0 0 0 0 |0
s t
General Solution:
x1=55+s-t
x2=-15+s-t
x3=25+s-t
x4=-35-s
x5=s
x6=t

The question is: if ED were closed due to roadwork, find the minimum flow along AC, using your results in the general solution.
Note: x2 = ED therefor x2=0, and AC is x6

Homework Equations





The Attempt at a Solution



I know x2=0 and no idea what to do with S and T...
what I did is set x2=0 so -15+s-t=0 so S=t+15
And sub it into the general solution you get:
x1=70
x2=0
x3=40
x4=-20+t
x5=15+t
x6=t

so x4≥0 when t≥20
x6≥0 when t≥0
So minflow is 0?

No, you are not thinking it through! You need ALL xi >= 0, so you need x4 >= 0 and so you need t >= 20. Just having t >= 0 is not good enough.

RGV
 
I am trying to find the MINIMUM flow so...
 
Back
Top