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Linear systems - circuit

  1. Mar 24, 2014 #1
    1. The problem statement, all variables and given/known data

    In attatchment


    2. Relevant equations

    Not sure How to come up with the other equations.

    3. The attempt at a solution

    Assuming a node is an element connected to two or more elements.

    1) Moving clockwise from V i1 to i2. Node one is between the negative side of the voltage source and first resistor.

    2) Node 2 is from first resistor to second resistor on the right and 3rd resistor down the middle.

    3) Node 3 is the top right hand corner between those two resistors.

    4) node 4 is the entire wire running down from the far right resistor and middle resistor and to the voltage supply.

    I also have two loops.
    Loop A encompass i2 i7 and i6 and loop B encompasses i3 i4 i5 and the middle resistor.

    I'm having trouble setting up the equations as all the references i've looked at have done the questions a little different. Mainly just using the junction method.
    current entering = current out.

    I have no experience on circuits so this is just what I make of the information I've read.

    eq 1 ) using node 1. i1 - i2 = 0
    eq 2) using node 2. i2 - i3 - i7 = 0
    eq 3) using node 3. i3 - i4 = 0
    eq 4) using node 4 i5 + i7 - i6 = 0
    eq 5) loop a i2*R + i7*R - V = 0
    eq 6) loop b i3*R + i4*R - i7*R = 0

    this is where i'm stuck and i'm unsure about my above equations. Is there a outside loop around the entire circuit or is there a node i have missed. I assume i need 7 equations for the 7 unknowns.

    Any help would be much appreciated. Kind regards.
     

    Attached Files:

  2. jcsd
  3. Mar 24, 2014 #2

    Ray Vickson

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    Science Advisor
    Homework Helper

    Basically, you just have three different currents, i1, i4 and i7. At the top t-junction you have i1 = i4 + i7, and this applies as well at the bottom t-junction (check this!). So that is one equation, and you need two more. Can you see what those other two equations must be?
     
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