Linear Transformations using polynomials

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The discussion revolves around the linear transformation D applied to polynomials in the space P3, defined as taking the derivative of a polynomial. Participants are tasked with finding the matrix representation MD of this transformation with respect to the standard basis {1, x, x², x³} and explaining why (MD)⁴ equals zero without matrix calculations. The key insight is that differentiation reduces the degree of a polynomial, and after four applications of D, any polynomial of degree at most 3 becomes zero. Thus, (MD)⁴ = 0 because all polynomials in P3 will have been reduced to a constant or zero polynomial. Understanding the effect of differentiation on polynomial degree is crucial to grasping the transformation's behavior.
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Homework Statement



Let P3 be the space of all polynomials (with real coefficients) of degree at most 3. Let
D : P3 -> P3 be the linear transformation given by taking the derivative of a polynomial.
That is
D(a + bx + cx2 + dx3) = b + 2cx + 3dx2:
Let B be the standard basis {1; x; x2; x3} of P3.
(a) Find the matrix MD of D with respect to the standard basis.
(b) Explain, without doing any matrix calculations, why (MD)4 = 0.

Homework Equations





The Attempt at a Solution


i know it may be a simple question but i don't even know where to begin
but in a attempt is
MD = [1 1 1 1;
0 2 3 0]
 
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Welcome to PF!

Hi mbud! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
mbud said:
Let P3 be the space of all polynomials (with real coefficients) of degree at most 3. Let
D : P3 -> P3 be the linear transformation given by taking the derivative of a polynomial.
That is
D(a + bx + cx2 + dx3) = b + 2cx + 3dx2:
Let B be the standard basis {1; x; x2; x3} of P3.
(a) Find the matrix MD of D with respect to the standard basis.
(b) Explain, without doing any matrix calculations, why (MD)4 = 0.

To find M, you only need the effect of M on the four basis elements. Sooo …

Hint: what is x2 as a vector? what is Dx2 as a vector? :wink:
 
More specifically, since the standard basis is 1, x, x2, and x3, take the derivative of each and write it in terms of those. The coefficients give each column of the matrix.
 
Thanks, for the help, but i still don't know how to explain (MD)^4 = 0
I can show it using matrices, but when it comes to words, I am flabbergasted.
 
mbud said:
Thanks, for the help, but i still don't know how to explain (MD)^4 = 0
I can show it using matrices, but when it comes to words, I am flabbergasted.

Hint: if V is the vector form of a polynomial ax3 + bx2 + cx + d, what is (MD)4V the vector of? :wink:
 
Differentiation does what to the degree of a polynomial? This is nothing to do with vectors, or vector spaces, or matrices - sometimes you just have to look at things and think for a little bit.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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