Linearizing Stefan-Boltzmann equation

J_I_F
Messages
2
Reaction score
0

Homework Statement


I want to linearize both the Stefan-Boltzmann equation and the adiabatic relation to draw a relationship between δL/L(0) and δR/R(0).


Homework Equations


Stefan-Boltzmann equation in the form of L=4πσ(R^2)(T^4)
Adiabatic relation TV^(γ-1) = constant


The Attempt at a Solution


I have L(0) + δL = 4πσ((R(0) + δR)^2)*((T(0) + δT)^4) for the S-B part, but don't know how to get it into this desired form:

δL/L(0) = (2δR/R(0)) + (4δT/T(0))
 
Last edited:
Physics news on Phys.org
J_I_F said:
I have L(0) + δL = 4πσ((R(0) + δR)^2)*((T(0) + δT)^4)

δL/L(0) = (2δR/R(0)) + (4δT/T(0))

So you have:

L_0+\delta L=4\pi\sigma(R_0+\delta R)^2(T_0+\delta T)^4

You will have to use a Taylor Expansion to expand the terms that can be considered very small. For example:

(a+x)^4=a^4(1+\frac{x}{a})^4 \approx a^4(1+\frac{4x}{a})

This only works when \frac{x}{a} is very small compared to 1, as is the case in your example. If you're still having trouble, show your work and we can go from there.
 
Last edited:
That helped a bunch, thanks.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top