Linearly Independent Vectors and Their Span: The Truth Behind <u,v,w> and <u,v>

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Homework Statement


Suppose u,v,w are linearly independent, is it true that <u,v,w> does not equal <u,v>


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The Attempt at a Solution


I started by defining what it meant to be linearly independent but am unsure where to go from there. I think the statement is true since the span <u,v> won't include any multiple of w but i can't give a solid proof
 
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Assume by contradiction that <u,v,w>=<u,v>. Then w\in &lt;u,v&gt;. Thus...
 
oh i think i get it, by assuming that we can say by definition

w=λ1u + λ2v
then there is now a non trivial solution to
λ1u + λ2v + λ3w=0 which contradicts the statement that u,v,w are linearly independent, is that right?
 
That's right!
 
Sweet, cheers
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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