The discussion focuses on finding the linearization of the function square root of sin(2x). Linearization involves creating a linear approximation of the function around a specific point using the first-order Taylor polynomial. The formula for linearization is f(x) ≈ f(a) + f'(a)(x - a), where x is near a. The conversation highlights that linearization is connected to calculus concepts, particularly the equation of the tangent line and differentiation. Understanding these principles is essential for solving the problem effectively.
#1
songoku
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Homework Statement
Find the linerization of square root of sin(2x)
Homework Equations
The Attempt at a Solution
I don't even know how to start. What is linearization?
It's just coming up with a linear approximation for the function about some point, that is, finding the first-order Taylor polynomial of the function expanded about a given point.
Assuming you want to use a linear approximation of the function for some x near a, the linearization is
f(x) \approx f(a) + f'(a)(x - a)
That's what vela was talking about when he mentioned the first-order Taylor polynomial. The "linear" part means that x appears to the first power only -- no higher powers.
BTW, this really seems like a calculus problem, so you probably should have posted it in the Calculus & Beyond section.
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#4
songoku
2,467
382
Hi vela and Mark
sorry I don't know that linearization is related to equation of tangent, so it's related to differential. thanks a lot !
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached.
The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter.
From my side, the only thing I could...