Little help with some simple Vector physics

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The discussion focuses on vector physics homework questions, specifically regarding the nature of vectors and vector addition. The first two answers provided, identifying a vector as a quantity with both magnitude and direction and confirming that the sum of two displacement vectors is also a displacement vector, are correct. For the third question, while the student calculated the resultant magnitude incorrectly by assuming the vectors were at right angles, the correct answer is 200, as it can be achieved through various vector arrangements. The maximum resultant magnitude of 240 occurs when both vectors point in the same direction, while the minimum is 160 when they point in opposite directions. Overall, the student is guided to reconsider their approach to vector addition and the implications of vector orientation.
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I just wanted to make sure I'm doing my homework correctly, please let me know if any of the following is incorrect, if anyone knows. most the questions are multiple choice but I am just posting what I found to be the answer. thanks,:

1- What type of quantity is characterized by both magnitude and direction?

Vector

2- When we add a displacement vector to another displacement vector, the result is:

a displacement vector

3- A student adds two vectors. One has a magnitude of 200 and the other has a magnitude of 40. Which of the following is the only possible chice for the magnitude of the resultant?

ok, so I am assuming the vectors are at a right angle so I used the phthalgorym therom or whatever (A squared + B squared = C squared) and I came out with 204, and one of my choices was 200 (the other choices were 100,260, and 40) I am just a little scetchy on this answer and wondering if I should have gone about it a different way.


Any input is greatly appreciated. Thanks.
 
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the first two are correct. you got the correct answer for the third one, but went about it incorrectly. Take a look at the answers given. With those two vectors could you add them in any way (doesn't have to be a right triangle) to make a vector of that length. For example, a vector of magnitude 260 could not be made from one of 200 and 40. For if they were added in the same direction it would only equal 240, the same type of logic applies to the other two incorrect ones. The answer of 200 could be made by a triangle (but not a right triangle) with two sides of length 200 and one of length 40.
 
Regarding 3 - the only possible choice seems to be 200. You can draw a vector in any direction, and say it has a magnitude of 200. Then, you draw a circle of radius 40 with the centre on the 'top' of the vector whose magnitude is 200 (on the arrowhead :biggrin: ). Then it's obvious that the least vector has a magnitude 160, and the greatest 240. So, 100, 40, and 260 fall off.
 
You got the first two ok. For the last one, I think you got the right answer, but why did you assume they are at right angles? The maximum possible magnitude is if both vectors are pointing in the same direction, in which case the magnitude would be 240, and the minimum is if they're going in opposite directions, giving 160. So you know the answer must be between 240 and 160.
 
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