Load line of transistor question

AI Thread Summary
To draw the load line of a transistor, it is essential to determine the saturation current and the collector-base voltage when the collector current is zero. The base-emitter junction is typically forward biased at around 0.6 to 0.7 volts, while the base-collector junction should be reverse biased to achieve accurate load line representation. The load line itself is derived from the circuit configuration and is a straight line formed by plotting the supply voltage against the current through a resistive load. The relationship between collector current (Ic) and collector-emitter voltage (Vce) is expressed through the equation Vcc = Vce + IcRc, which helps in plotting the load line on the transistor's characteristic curves. Understanding these principles is crucial for analyzing transistor behavior in various circuit configurations.
Outrageous
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In order to draw the load line of transistor, we have to find out the saturation current (where the voltage is minimum or zero) and voltage of collector-base when collector current is zero.

In order to calculate maximum saturation current, we have to forward biased the base-emitter, and reverse biased the base -collector and then get the voltage of collector-emitter to be zero(V of collector minus voltage of emitter equals to zero), right??


Thank you
 
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I think 'we have to forward biased the base-emitter, and reverse biased the base' instead of both forward because when we forward both we can't get a constant curve at saturation region, correct?
 
the base-emitter junction is always forward biased as long as the transistor is not in full "cut-off" (where the collector current is zero). so, from the POV of the load line, the base-emitter is forward biased, usually by about 0.6 volts.
 
rbj said:
the base-emitter junction is always forward biased as long as the transistor is not in full "cut-off" (where the collector current is zero). so, from the POV of the load line, the base-emitter is forward biased, usually by about 0.6 volts.


what is POV?
The base-emitter is usually 0.7V.
How to draw a load line?
 
Outrageous said:
what is POV?
The base-emitter is usually 0.7V.
How to draw a load line?

POV = "point of view"
 
Maybe this will help:



.
 
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First of all there is not one load line for a transistor.

There are many and they depend upon the circuit configuration.

Having said that, for a resistive load the load line is a straight line so you only need to find two points and join them to be able to draw one.

To draw a load line for R ohms on the collector current (y axis) v collector voltage (x axis) curves:

1)Locate the point of the voltage axis corresponding to the supply voltage.

2)Locate the point on the current axis which the supply voltage would drive through R ohms.

3) Join these two points to form the load line for R ohms.

go well
 
Thank you, understand already.

berkeman said:
Maybe this will help:



Studiot said:
First of all there is not one load line for a transistor.

There are many and they depend upon the circuit configuration.

Having said that, for a resistive load the load line is a straight line so you only need to find two points and join them to be able to draw one.

To draw a load line for R ohms on the collector current (y axis) v collector voltage (x axis) curves:

1)Locate the point of the voltage axis corresponding to the supply voltage.

2)Locate the point on the current axis which the supply voltage would drive through R ohms.

3) Join these two points to form the load line for R ohms.
 
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Outrageous said:
The base-emitter is usually 0.7V.

okay. whatever. from long ago, when i was a graduate teaching assistant (and i was teaching a lab), it was most often 0.6v for silicon.

How to draw a load line?

well, your transistor curve is that of a function I_c as a function of V_{ce} for various I_b. so given an I_b, you still don't know what I_c is without also knowing V_{ce}. the load line is another equation that relates I_c and V_{ce}. and that equation comes from the rest of the circuit (assuming no R_e:

V_{cc} = V_{ce} + I_c R_c

or

I_c = \frac{1}{R_c} ( V_{cc} - V_{ce} )

plotting that equation on top of the transistor curves is your load line.
 
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rbj said:
okay. whatever. from long ago, when i was a graduate teaching assistant (and i was teaching a lab), it was most often 0.6v for silicon.



well, your transistor curve is that of a function I_c as a function of V_{ce} for various I_b. so given an I_b, you still don't know what I_c is without also knowing V_{ce}. the load line is another equation that relates I_c and V_{ce}. and that equation comes from the rest of the circuit (assuming no R_e:

V_{cc} = V_{ce} + I_c R_c

or

I_c = \frac{1}{R_c} ( V_{cc} - V_{ce} )

plotting that equation on top of the transistor curves is your load line.

Understand.
when there is R_e ,we can use the equation in this (transistor load line)
http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/loadline.html
But for this case , our Ic=Ib, correct?
 
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