Locate the Centriod of a Line Problem

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The discussion revolves around locating the centroid of a line, with the book providing values of Xbar= 5.74 and Ybar= 1.28. The user expresses confusion over the dimensions and the datum used for calculations, trying both the bottom left and right corners without success. They mention using the formula 2r/π to calculate Ybar for a radius line but are unsure if they need to apply it for both coordinates. There is a misunderstanding regarding the use of π in their calculations, indicating a need for clarification on the formulas involved. The user continues to struggle with arriving at the correct centroid values despite multiple attempts.
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I am trying to locate the centriod of a line and I am not getting to the end.

The answer the book gives is Xbar= 5.74 and Ybar= 1.28

I am getting confused on where they are trying to call out the dimensions from what datum.

Total line length is 18.

L5 = ybar= 2.5 xbar= 0
L8= Ybar= 0 xbar= 4
L5radius = Ybar= 3.183 Xbar= 8 (would this be right technically?)

I am using my datum from the bottom left corner but I also tried to use bottom right corner and still I am not coming up with the correct answer...I am adding total xbar and dividing TL/Xbar vice verse for Ybar but I can't seem to come up with the answers.
I used the formula 2r/Pie to get my ybar for the radius line.
 

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hi smashbrohamme! :smile:

(have a pi: π :wink:)
smashbrohamme said:
I used the formula 2r/Pie to get my ybar for the radius line.

don't you need it for both y and x ?
 
im still not coming up with the correct answer...I am multiplying the 5radius to Pi, to get the actual line length for the radius5...but I am doing something wrong here. and I have been trying everything
 
hi smashbrohamme! :smile:

(what happened to that π i gave you? :confused:)
smashbrohamme said:
… I am multiplying the 5radius to Pi, to get the actual line length for the radius5

no, π/2 :wink:
 
what does n mean?
 
smashbrohamme said:
what does n mean?

it's not n it's π (pi) :biggrin:

(copy it and use it!)
 
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