Locating Object & Image with a Converging Lens

AI Thread Summary
A converging lens with a 7 cm focal length produces a 1.10 cm tall erect image from a 4 mm tall real object located to the left of the lens. The second scenario involves a converging lens with a 12 cm focal length that creates a virtual image 5 mm tall, positioned 19 cm to the right of the lens. To solve these problems, the lens equation (1/f = 1/o + 1/i) and the magnification formula (m = -i/o) are essential. Users are encouraged to explore a simulation program for better visualization of these concepts. Understanding the object and image locations requires applying these equations accurately.
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1) Aconverging lens with a focal length of 7 cm forms an image of a 4 mm tall real object that is to the left of the lens. The image 1.10 cm tall and erect.
Where is the object located?
Where is the image located?
2) A converging lens with a focal length of 12 cm forms a virtual image 5 mm tall, 19 cm to the right of the lens.
Determine the position of the object. (Give the object distance with the correct sign).
Determine the size of the object.
 
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You'll need the lens equation: 1/f = 1/o + 1/i, and the definition of linear magnification: m = -i/o.

Look up how these equations are used and give the problems a try.
 
eku_girl83 said:
1) Aconverging lens with a focal length of 7 cm forms an image of a 4 mm tall real object that is to the left of the lens. The image 1.10 cm tall and erect.
Where is the object located?
Where is the image located?
2) A converging lens with a focal length of 12 cm forms a virtual image 5 mm tall, 19 cm to the right of the lens.
Determine the position of the object. (Give the object distance with the correct sign).
Determine the size of the object.
There is a good simulation program picture what about it
http://www.geocities.com/mrfarag
 
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