i need some help understanding the following:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]y=\frac{\sqrt{x}}{2^x}[/tex]

[tex]y=lnx^{{lnx}^{{lnx}^{{lnx}^{{lnx}}}}}[/tex]

i have some idea how to do the first one. i think it goes like this:

[tex]y=\frac{\sqrt{x}}{2^x}[/tex]

[tex]ln y=ln (2^x)-ln(\sqrt{x})[/tex]

[tex]\frac{1}{y}y'=xln (2)-\frac{1}{2}ln(x)[/tex]

[tex]y'=\frac{\sqrt{x}}{2^x}[xln (2)-\frac{1}{2}ln(x)][/tex]

am i on the right track? or should i be doing something else?

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# Log derivatives

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