Log Help: Determine Expression Equal to log x

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To determine an expression equal to log x from the equation y = x^2(a + z), the discussion emphasizes the importance of applying logarithmic properties. Taking the logarithm of both sides leads to log y = log(x^2(a + z)), which simplifies to log y = 2(a + z) log x. Participants express confusion about the steps and properties of logarithms, particularly the distinction between log(y)/log(x) and log(y/x). Ultimately, the correct expression for log x is derived as log x = log y / (2(a + z)). The conversation highlights the need for a solid understanding of logarithmic rules to solve such problems effectively.
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I've been looking through my textbook for a question even remotly similar and no luck, if you could get me started witht this question I'd love to do it and then I'll write what I got and write it here.

If y=x^2(a+z) determine an expression equal to log x. (Hint: you will need to take the log both sides at some point)
 
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Would this property help you?

\log a^b = b\log a
 
uhh not really, you could elaborate on that idea though?

Would it be like...

logx = xlog

then xlog^2(a+z)

Sorry I'm really confused/
 
If you take the log of both sides, you end up with:

\log y = \log x^2^(^a^+^z^)

See the similarity between the b in my earlier equation and 2(a+z)? >_>
 
okay... I kind of get it...

I did this...

log(y/x) = 2a + 2z

so that's logx = (2(a+z))/y

I'm still stuck
 
The question asks, determine an expression for log x? I'm confused about what you are trying to accomplish. Following from:

\log y = \log x^2^(^a^+^z^)
\log x = \frac{\log y}{2(a+z)}
 
Pepsi, please post all coursework related questions in the Homework Help section.

Also, you need to relearn the properties of logarithms first. Please go over this chapter in your text again. For instance, log(y)/log(x) is not the same as log(y/x).
 
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