Verify: Is a^(log n) = n^(log a)?

[bodensee9]

Hello:

I seem to recall a vague truth that a^(log n) = n ^ (log a)? Can someone verify?

Thanks.

 

[neutrino]

Yes, they are. Take the logarithm of both sides and see for yourself. Of course, this is all assuming that a and n take on appropriate values.