Logarithms - where does the coefficients come from

[weeman203]

for example
3 log (base5) 2 - (1/2)log (base5) 9

how would someone come to work this out
i know that you are suppose to divide the 2nd part by the 1st
but I am not sure where does the coefficients come in
would that mean you multpily the coefficients

 

[jonnhannah]

rewrite the second one so that it is - log (base5) 3
taking the square root of 9
do the same for 2^3 so that it is now 8
log (B5) 8 - log (B5) 3

 

[weeman203]

rewrite the second one so that it is - log (base5) 3
taking the square root of 9
do the same for 2^3 so that it is now 8
log (B5) 8 - log (B5) 3

OH yeah, now i remember thanks =D