daselocution
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Homework Statement
First part of the problem:
Newton’s second law is given by F=dp/dt. If the force
is always perpendicular to the velocity, show that F=gamma*m*a, where a is the acceleration.
Second part of the problem: Use the result of the previous problem to show that
the radius of a particle’s circular path having charge q traveling with speed v in a magnetic field perpendicular to the particle’s path is r = p/qB. What happens to the radius as the speed increases as in a cyclotron?
Homework Equations
p=gamma*m*v
Fmagnetic field = qv x B = (in this case b/c of θ=90º) qvB
The Attempt at a Solution
The first part: I am thinking that since the force is perpendicular to the path of motion, that the speed of the particle will not change, only it's direction--is this logical? If this were indeed the case, then I would solve as follows (and get the answer as directed):
F=dp/dt=d(m*gamma*v)/dt = m*gamma*d(v)/dt
=m*gamma*a
where dv/dt=a and where speed is unchanging so gamma should be constant
Second part of the problem:
F=m*gamma*acceleration=qvB
At this point I'm entirely unsure of how to proceed. I remember that in classical physics a=v2/r, but I don't know if that applies here.
If it does indeed apply here, then the answer seems to be straightforward:
F=m*gamma*acceleration=m*gamma*v2/r=qvB
r=m*v*gamma/(qb)=p/(qB)
Thus, as the speed increases in a cyclotron, the radius should increase as well