Lovers Reunited: Calculating Time Apart

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A young couple is 30 meters apart in an airport, with the husband accelerating from rest at 0.7 m/s² and the wife moving at a constant speed of 3.4 m/s. The problem requires calculating the time it takes for them to meet. The wife's distance traveled can be expressed as x = 3.4t, while the husband's distance is 30 - x. By setting up the equations for their movements, the time until they reunite can be determined.
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I have a question which reads as follows:
After a long time apart, a young couple in love are running towards each other in the hallways of an airport. They are 30.0m apart. The husband is accelerating from rest at a rate of 0.7m/s2 (2 is squared), and the wife was moving at 3.4m/s and maintains her speed. How much time passes before they are finally together?

I just need help gathering the info from the question.
What I have so far:
Husband
-v1=0m/s
-acceleration=0.7m/s2 (2 is squared)
-distance=30.0m
-time=?

Wife
-v1=3.4m/s
-distance=30.0m
-t=?

Thanks in advance:)
 
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One may infer from the problem that the husband starts accelerating when his wife is 30 m from him. During the same period of time, each is traveling to some common point.

Let x be the distance traveled by the wife, and then knowing the velocity that the wife travels, 3.4 m/s, the distance as a function of time is simply x = 3.4 t (t in seconds).

In the same time, when they meet, the husband must have traveled 30-x.
 
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