Lower pH w/ Equal Vol 0.60M NaOH: 0.70 M KOH

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The discussion revolves around determining which solution would have a lower pH after adding an equal volume of 0.60 M NaOH. The correct answer is 0.70 M KOH, as adding NaOH increases the hydroxide ion concentration, leading to a left shift in equilibrium and a higher pH. The misconception arises from the belief that adding a strong acid like 0.30 M HCl would lower the pH, but the question specifically asks about the effect of adding NaOH. Participants clarify that in all scenarios, the pH increases after NaOH addition. Ultimately, the focus is on understanding the effects of hydroxide ions on pH levels.
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Homework Statement


To which of the following would the addition of an
equal volume of 0.60 M NaOH lead to a solution
having a lower pH? (a) water, (b) 0.30 M HCl,
(c) 0.70 M KOH, (d) 0.40 M NaNO3.

2.The attempt at a solution
t
he correct answer is 0.70 M KOH, and they say that by adding more OH you are producing a left shift. Okay, that's cool.

My answer is 0.30 M HCl, this is because adding a strong acid will increase H+ concentration, OH- concentration will go down, therefore pH will decrease. Why is this wrong?
 
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ThatDude said:

Homework Statement


To which of the following would the addition of an
equal volume of 0.60 M NaOH lead to a solution
having a lower pH? (a) water, (b) 0.30 M HCl,
(c) 0.70 M KOH, (d) 0.40 M NaNO3.

2.The attempt at a solution
t
he correct answer is 0.70 M KOH, and they say that by adding more OH you are producing a left shift. Okay, that's cool.

My answer is 0.30 M HCl, this is because adding a strong acid will increase H+ concentration, OH- concentration will go down, therefore pH will decrease. Why is this wrong?

You might have misread the question: acid is not being added.
 
Perhaps I am missing something, but I don't get the question - in each case after adding NaOH pH goes up, it never goes down, thus it can't be lower.
 
I think you are slightly missing it. :oldwink:
 
Geez, got it. What a brain fart o0)
 
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