Can You Correctly Lower Tensor Indices Using the Metric Tensor?

  • Thread starter Thread starter beans73
  • Start date Start date
  • Tags Tags
    Indices Tensors
beans73
Messages
12
Reaction score
0

Homework Statement



I have a tensor X^{μ\nu} and I want to make this into X_{μ\nu}. Can I do this by simply saying X_{μ\nu}=\eta_{μ\nu}\eta_{μ\nu} X^{μ\nu} ??
 
Physics news on Phys.org
beans73 said:

Homework Statement



I have a tensor X^{μ\nu} and I want to make this into X_{μ\nu}. Can I do this by simply saying X_{μ\nu}=\eta_{μ\nu}\eta_{μ\nu} X^{μ\nu} ??

You have the right idea, but your indices are incorrect (it's ambiguous which indices are to be contracted with which other indices). Try introducing some new indices for the contracted ones, see if you can make it unambiguous.

for example, you could write:

V^{\mu} = \eta^{\mu \nu} V_{\nu}

Which makes it clear which index of eta is contracted, and which isn't. In this case, eta is symmetric so it doesn't really matter, but for a general tensor with two or more indices it does matter.

To explain why it's ambiguous, consider this:

Does X_{μ\nu}=\eta_{μ\nu}\eta_{μ\nu} X^{μ\nu} mean X_{μ\nu}=\eta_{μ\nu}(\eta_{μ\nu} X^{μ\nu})? In that case you would get a tensor proportional to eta. This is obviously not what you were thinking, but if someone saw that expression and didn't know that you were trying to make X_{\mu\nu}, they might think you meant to make a tensor proportional to eta.

So just a good rule of thumb, never repeat an index unless it is supposed to be summed.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top