Mach Value64: Calculate Jet Speed after 41s at 12ms2

[soulja101]

Homework Statement

If the temperature is 12 degrees and a jet accelerates at rest at 12ms2 for 41s, then what is the Mach value for the jet at the end of 41 seconds

Homework Equations

mach#=vovs
speed of sound equation

The Attempt at a Solution

v=12degrees
a=12ms2
v=339,08ms
m#=vo/vs

 

[marcusl]

Homework Statement

If the temperature is 12 degrees and a jet accelerates at rest at 12ms2 for 41s, then what is the Mach value for the jet at the end of 41 seconds

Homework Equations

mach#=vovs
speed of sound equation

The Attempt at a Solution

v=12degrees
a=12ms2
v=339,08ms
m#=vo/vs

Your statement of the problem has numerous flaws. I assume the jet accelerates from rest, and that you meant "t=12degrees" above. Careful also to use acceleration units of meters per second^2, not m-s^2. Finally your value for v is incorrect.

What is the equation giving velocity in terms of acceleration and time? Once you have that you'll need the speed of sound at 12 degrees to finish the problem...

 

[m2003]

= 339,08/12= 28,26

Based on the given information, the Mach value for the jet at the end of 41 seconds is approximately 28.26. This value can be calculated using the formula for Mach number, which is the ratio of the jet's velocity (v) to the speed of sound (vs). In this case, the jet's velocity can be calculated by using the given acceleration (a) and time (t) using the equation v=at. The speed of sound at a temperature of 12 degrees can be found using the speed of sound equation. By plugging in the values and solving for the Mach number, we get a value of 28.26, indicating that the jet is traveling at a speed 28.26 times the speed of sound. However, it's important to note that this is a theoretical calculation and may not accurately reflect the actual speed of the jet. Other factors such as air resistance and engine efficiency may affect the jet's speed.