Magnet with negative charge in gaussian surface?

AI Thread Summary
A bar magnet with a negative charge uniformly spread over it does not reverse the direction of its magnetic field. The presence of a static charge does not influence the magnetic field, which remains oriented from north to south. For the Gaussian surface analysis, the total electric flux through the top end cap A is negative due to the negative charge, while the total electric flux through the entire surface is also negative. The total magnetic flux through both the top end cap A and the entire Gaussian surface is zero, as magnetic monopoles do not exist. Understanding these principles is crucial for exam preparation in electromagnetism.
marshmallow
Messages
4
Reaction score
0
i would really appreciate if someone could help me out with this one. i m preparing for an exam and this question is a question from papers of previous years and its bugging me because it seems very specific in that i can't seem to find anything like it in textbooks.

what i m mainly stuck on is if a negative charge is spread over the magnet does this mean the direction of the magnetic field reverses from north to south to south to north?



A bar magnet has been given a negative charge -Q, spread uniformly over the magnet.

the Gaussian cylinder shown at right with end caps A and C and a curved side B. the centre of cap A coincides with the centre of the bar magnet.

(a) is the total electric flux through the top end of the cap, A, positve, negative or zero?

(b) is the total electric flux through the entire gaussian surface, consisting of sides A,B, and C, positive, negative, or zero?

(c) is the total magnetic flux through the top end cap, A, positive, negative or zero?

(d) is the total magnetic flux through the entire gaussian surface, consisting of sides A, B, and C, positve, negative, or zero?
 

Attachments

  • mg.jpg
    mg.jpg
    7.2 KB · Views: 431
Physics news on Phys.org
marshmallow said:
what i m mainly stuck on is if a negative charge is spread over the magnet does this mean the direction of the magnetic field reverses from north to south to south to north?
No. A static charge has no effect, whatsoever, on the magnetic field.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top