Magnetic dipole moment energy question

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The discussion revolves around the calculation of magnetic dipole moment energy in an external magnetic field. The user notes a discrepancy between two energy equations: U_m = (1/2)μ·B and the force equation derived from the integral of J×B, which yields -μ·B. The difference arises because the first equation accounts for double counting in current distributions, necessitating the 1/2 factor, while the second equation considers only external currents. The positive sign in the first equation is attributed to an EMF source maintaining constant current, while the second equation reflects a situation without energy supply. Ultimately, both approaches yield the same force despite the differences in energy expressions.
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Hello, I have this problem. I calculated the dipole energy of a dipole moment in an external field using the equation U_m=\frac{1}{2}\int\vec{A}\vec{J}dr^3=\frac{1}{2} \vec{\mu}.\vec{B} however when the force on a dipole is calculated using \int\vec{J}\times\vec{B}dr^3 the formula obteined for the energy is -\vec{\mu}.\vec{B}
I don't understand the difference, are they supposed to be defferent?
 
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The 1/2 in your first equation arises because the integral is over all current distributions. The 1/2 takes care of double counting that takes place in that case.
The B field in the second equation is due to only external currents (not part of mu), so the 1/2 does not arise.

The + sign in the first equation is due to the fact that the current is kept constant by an EMF source that provides energy to keep the current constant. Then, the force is given by +grad U. In the second equation, no energy is supplied, so F= -grad U.
Each case thus gives the same force.

You can look at <http://arxiv.org/pdf/0707.3421.pdf>
 
Thanks, I will take a look
 
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