Magnetic Field above a Rectangular Circuit

AI Thread Summary
The discussion focuses on calculating the magnetic field above a rectangular circuit using the Biot-Savart Law. The current is constant, and the symmetry of the setup suggests that the magnetic field will be directed along the z-axis. The main challenge arises from the changing angle between the differential length element and the position vector during integration. Participants confirm that the angle does indeed change throughout the integral, which is a critical consideration in the calculation. This topic is commonly addressed in electromagnetic theory, particularly in texts like Griffiths' "Introduction to Electrodynamics."
Contingency
Messages
41
Reaction score
0

Homework Statement


On the XY there lies a conducting wire-rectangle with sides parallel to the axis.
The current is given and constant.
What is the magnitude of the magnetic field along an axis parallel to the z axis, going through the intersection of the rectangle's diagonals?

Homework Equations


\vec { dB } =\frac { I }{ c{ \left| \vec { r } \right| }^{ 3 } } \vec { dl } \times \vec { r }

The Attempt at a Solution


Due to symmetry, I can expect the field along this axis to be in the z direction. I can integrate along just one of each pair of the circuit's sides and double the result.
What I'm having trouble with is the cross product in Biot-Savart's Law - it seems to me that the angle { \theta }_{ \vec { dl } ,\vec { r } }changes throughout the integral. If this is true then it seems the calculation of the field is not too easy..
I'd just like to make sure I'm correct before I get into it - does { \theta }_{ \vec { dl } ,\vec { r } }change throughout the integral?
 
Last edited:
Physics news on Phys.org
Remind yourself how the calculation goes for an infinite line of current using the Biot-Savart law. The same calculation will apply to each piece of the loop, just with finite integration bounds.
 
I haven't calculated that field with Biot-Savart.. But I presume the implied answer is that the angle changes and this is not negligible.. Right?
 
Yes, the angle changes. It is usually one of the first calculations done in any EM text after introducing the Biot-Savart law. You can take at look at "Introduction to Electrodynamics" by Griffiths, for instance.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top