Magnetic field due to a solenoid

AI Thread Summary
The discussion revolves around the interpretation of a problem involving a solenoid, specifically the phrase "half number of turns are wound." Participants express confusion over the implications of cutting the solenoid into four parts, leading to a reduction in both length and number of turns. There is a consensus that the winding density is halved for each quarter, but the phrasing of the problem is deemed ambiguous and poorly constructed. The solution options are debated, with one interpretation suggesting that the total number of turns is halved before being distributed across the reduced length. Overall, the complexity and unclear language of the problem statement hinder a straightforward understanding.
Jahnavi
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Homework Statement


solenoid.png


Homework Equations

The Attempt at a Solution



I am having trouble interpreting the language of the problem statement . What does it mean that "half number of turns are wound " ?

When the solenoid is cut , the length becomes 1/4th of the original and number of turns also become 1/4th of the original .

I think the problem is not difficult if only I could understand the question .

Thanks .
 

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That is a strange question. Are the four equal parts picked up again later?
If not, I don't understand that part. I would assume the density of the windings (windings per length) is halved.
 
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mfb said:
Are the four equal parts picked up again later?

I think so .

mfb said:
I would assume the density of the windings (windings per length) is halved.

How ?

What does it mean "half number of turns wound on anyone piece " ?
 
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Well, the sentence does not use correct English grammar, so it is a bit speculation, but I interpreted it as "For each quarter, we halve the winding density". For the following question this means the quarters don't matter.
Jahnavi said:
I think so .
Can you show the full problem with its context?
 
mfb said:
Can you show the full problem with its context?

That is all I have . This is an objective type MCQ from a test paper .

mfb said:
I interpreted it as "For each quarter, we halve the winding density".

This interpretation gives option 4) . Right ?

mfb said:
For the following question this means the quarters don't matter.

Could you explain this .
 
Jahnavi said:
This interpretation gives option 4) . Right ?
Sure.
Jahnavi said:
Could you explain this .
You didn't use the part about quarters to arrive at the answer of B/2, right?
 
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Option 2) is the answer given .Please see the solution .

Solution3.png


I think what they ( paper setters ) are trying to do is halving the total number of turns (before the solenoid is cut ) and then fitting those N/2 turns in the length L/4 ( after the solenoid is cut in four ) . Strange interpretation :wideeyed: .

Please let me know if the official solution makes sense to you .
 

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I can see how you could interpret the problem that way, but the phrasing is unnecessarily complicated and ambiguous.
 
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Thanks !
 
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