Magnetic Field due to Time Dependent Current

AI Thread Summary
The discussion revolves around calculating the magnetic field B around a long, straight copper wire carrying a time-dependent current described by sin(ωt). Ampere's Law is applied, leading to the equation μ(sin(ωt)) = B∮dl, where B is assumed constant around the conductor. The challenge arises in incorporating the wire's resistivity (ρ) and permittivity (ε), with suggestions that these parameters may not be necessary for the magnetic field calculation. It is noted that the solution relies on a quasi-static approximation, assuming copper's good conductivity and a specific relationship between ω, ε, and ρ. Clarifying these assumptions is essential for a complete understanding of the solution's validity.
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Homework Statement


A long, straight, copper wire has a circular cross section with radius R, resistivity p and permittivity ε. If the current through the wire at any time t is sin(ωt) amperes, find the magnitude of the magnetic field B at time t a distance r from the centre of the wire for r > R.


Homework Equations


Ampere's Law:
μI = Bdl
Possibly Law of Biot-Savart:
B = μ/4π * (Idl x r)/r^2

The Attempt at a Solution


μI = Bdl
μ(sin(ωt))=∮B*dl (Since they are parallel)
μ(sin(ωt))=B∮dl (Since B is constant radially around conductor)

This is where I reach a bottleneck. I don't know how to incorporate ε (since this is a magnetic field). I assume resistivity would be used in calculating the current I, but I don't know how that ties into the sinusoidal function.
 
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maybe you don't need to use ##\epsilon## and ##\rho##. Also, you have already used a certain kind of assumption about ##\epsilon## and ##\rho## to get your answer. So maybe the question is hoping that you will explicitly state this assumption about ##\epsilon## and ##\rho##.

Your answer is essentially a kind of quasi-static approximation. (Not the most general answer for this question). But you have implicitly used the fact that copper is a good conductor, and assumed a certain relationship between ##\omega##, ##\epsilon## and ##\rho##. I'm not sure if that was your deliberate intention, or if you missed a few steps. But I think you have the answer they were looking for, but maybe without explaining under what approximation this answer will work.
 
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