Magnetic Field Intensity and Point Charges

AI Thread Summary
The discussion focuses on calculating the net magnetic field produced by two moving positive point charges at a specific point P. The first charge, q_1, has a magnitude of 6.90 microC and moves at 3.20×10^6 m/s, while the second charge, q_2, has a magnitude of 2.90 microC and moves at 9.40×10^6 m/s. The participant expresses uncertainty about the signs in their calculations for the magnetic fields generated by each charge and whether the fields are in opposite directions. After performing the calculations, they arrive at a total magnetic field of -(1.37×10^-4 T) directed out of the page, seeking confirmation on the accuracy of their results. The discussion highlights the importance of correctly applying the cross product in determining the magnetic field direction and magnitude.
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Homework Statement



Positive point charges q_1= 6.90 microC and q_2= 2.90 microC are moving relative to an observer at point P as shown in the figure. The distance from the observer to either charge is originally d = 0.190 m.The two charges are at the locations shown in the figure. Charge q_1 is moving at a speed of v_1 = 3.20×10^6 m/s and q_2 is moving at a speed of v_2 = 9.40×10^6 m/s.

a. What is the magnitude of the net magnetic field they produce at point P ?
b. What is the direction of the net magnetic field they produce at point P ?

yf_Figure_28_29.jpg


Homework Equations



See below.

The Attempt at a Solution


I think I mixed up my signs for the cross product of v and r. Are the two fields in opposite directions? Any advice on those parts are appreciated.


B_1 = (mu_0/4*pi)*[(q*v vector*r vector)/(r^3)]

v vector = 3.20*10^6 m/s*i
r vector = (-0.190 m)*j

v vector*r vector = (3.20*10^6 m/s)i*(-0.190 m)j = -60800 m^2/s*k

B_1 = [(1*10^-7 T*m/A)*(6.90*10^-6 C)(-60800 m^2/s*k)]/[0.190 m]^3

= (-6.12*10^-5 T)*k ??


B_2 = (mu_0/4*pi)*[(q*v vector*r vector)/(r^3)]

v vector = -9.40*10^6 m/s*i
r = 0.190 m*j

v vector*r vector = (-9.40*10^6 m/s*i)*(0.190m*j) = -1786000 m^2/s

B_2 = [(1*10^-7 T*m/A)*(2.90*10^-6 C)(-1786000 m^2/s*k)]/[0.190 m]^3
= (-7.55*0^-5 T)*k ??

B_total = (-6.12*10^-5 T)*k - (-7.55*0^-5 T)*k = -(1.37*10^-4 T)*k out of the page?? (negative z-axis?)

Thanks.
 
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Can anyone please check over my workings, particularly my signs?

Thank you very much.
 
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