Magnetic field lines in a ring magnet

AI Thread Summary
Magnetizing a hollow cylindrical ring magnet with a straight current-carrying wire creates magnetic field lines that run inside the cylinder in a specific orientation. While there may be no significant magnetic field lines outside the iron body, a weak Biot-Savart field does extend into the surrounding air due to the high reluctance of air compared to iron. For a cylindrical hollow magnet or a configuration of two horse shoe magnets, magnetic field lines will exist outside the magnet, attracting iron particles. The geometry of the magnet affects the field lines, which can appear as ovals when the ring is stretched into a tube. Overall, the discussion highlights the complexity of magnetic field patterns and their visual representation.
Himanshu_6174
Messages
12
Reaction score
0
Say if I magnetize a hollow cylindrical ring magnet by placing a staight current carrying wire along its axis. It will be magnetized with magnetic field lines running inside the cylinder clockwise or anticlockwise! So there will be no magnetic field lines outside the iron body? If I have a cylindrical hollow magnet or a magnet made by attaching two horse shoe magnets with magnetic field lines running along its length then, will there be any magnetic field lines outside the magnet? I think there will be because iron particles placed outside will get attracted to it. But how will these lines look?
 
Physics news on Phys.org
If you take a round bar magnet and drill a hole thru the axis of nort to south. It will still behave like a bar magnet but it's geometry is like a cylinder. The magnetic field lines circle around in north south plane it and through the drilled hole too.

http://www.davidpace.com/images/stories/em/em2im5.png
 
Last edited by a moderator:
here, the domain run in circular fashion within the body. How will the magnetic field lines look?
 

Attachments

  • dd.jpg
    dd.jpg
    7.6 KB · Views: 1,849
200px-VFPt_dipole_magnetic3.svg.png

This is the only orientation I have seen. If you stretch the ring into a tube the field lines would stretch into ovals across the length radiating around the circumference of the tube.
 
jerromyjon said:
200px-vfpt_dipole_magnetic3-svg-png.75929.png
This is somewhat off-topic, but I have to mention it. I've never seen that particular field pattern before. It reminds me so much of a spider that I'm inspired to seek out other physics phenomena that have secondary associations and make an art project of it.
 
Himanshu: The field around the wire is a Biot-Savart field and the ring will be magnetized with this field orientation. However, the Biot-Savart field extends to infinity so there will be a weak field outside of your magnet with the same orientation. The field is weak because of the high reluctance of air as compared to the iron ring.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top