Magnetic Field of 60-Turn Coil w/ 0.2m Radius & 4A Current

Thread starter pooka
Start date Jul 5, 2008
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Coil Current Field Magnetic Magnetic field Radius

AI Thread Summary

The discussion focuses on calculating the magnetic field at the center of a 60-turn coil with a radius of 0.2 m carrying a current of 4 A. The correct formula to use is B = (μ0)(N)(I)/(2r), where μ0 is the permeability of free space, N is the number of turns, I is the current, and r is the radius. There is clarification that the radius, not the diameter, should be used in the formula. The participants agree that the coil should be treated as a flat circular coil rather than a solenoid. This approach leads to an accurate calculation of the magnetic field generated by the coil.

Jul 5, 2008

pooka

What is the magnetic field at the center of a 60-turn coil carrying a current of 4 A, if it has a radius of 0.2 m?

I was thinking of using the equation B=(mu0)(N/l)(current)

But I was wondering do I use the radius for l or do I use the diameter?

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Jul 5, 2008

rock.freak667

Homework Helper

I think you need to consider it as flat circular coil instead of a solenoid

B=\frac{\mu_0 NI}{2r}

Jul 5, 2008

pooka

thanks!

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