Magnetic Field outside AC Solenoid

AI Thread Summary
To calculate the magnetic field (B) outside an AC-driven solenoid, one approach is to adapt existing DC formulas by substituting the current variable with a time-dependent function. For instance, using a sinusoidal function like i = 6sin(377) can yield a trigonometric time-varying solution. Additionally, searching for "Transient field outside of solenoid" may provide relevant resources and insights. The discussion emphasizes the need for specific expressions tailored to AC conditions, which differ from those for DC. Engaging with these strategies can assist in deriving the desired magnetic field calculations.
craig_e
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Hi

I have scoured the internet trying to find the right expression to calculate the magnetic field (B) outside of an AC driven solenoid. All i keep getting is stuff for DC driven or inside the solenoid.

Can anyone help?

thanks

Craig
 
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Hmmm

Without looking up any references, what comes to mind is simply plugging in the time domain function of the current into any DC formula you have.

For example.. the formula probably has a capital I in it... change that to small i then find the time domain function for i

like,

i = 6sin377

You'll end up with an answer that is also a trigonometric time varying function...
 
This might help:
http://www.physics.adelaide.edu.au/mathphysics/abstracts/ADP-AT-96-3.html

Try doing a google search using the term "Transient field outside of solenoid". You can also replace field with Magnetic or B-Field.

Good Luck
 
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