The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 8.20 106 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.10 10-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were each of the following. (a) an electron (b) a proton Relevant Equations: F=I*L*B F=qvB charge electron and proton= +/- 1.6E-19 ATTEMPT: i plugged in the charges into q then then velocity and the magnetic field and got the answer, now i'm confused on how to find the radius. please help. thanks!