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Magnetic fields and currents

  1. Nov 10, 2006 #1
    Question: 1. a) what is the force per meter on a wire carrying a 9.80-A current when perpendicular to a 0.80-T magnetic field? b) What if the angle between the wire and the field is 45°?

    For part a) I know that F = ILB, where I is the current, L is the length of the wire and B is the size of the magnetic field.

    Therefore F = 9.80 x L x 0.80
    = 7.84 x L

    But how can you work out the force when you don’t know what L is?

    For part b) I know that F = ILB sin θ

    I’m not sure how to approach the problem other than what I have expressed. Any help you can offer will be great.....thanks :D
     
  2. jcsd
  3. Nov 10, 2006 #2

    Hootenanny

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    The clue is in the question :wink:
     
  4. Nov 10, 2006 #3
    oh yeh! Thanks so much!! :D
     
  5. Nov 10, 2006 #4

    Hootenanny

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    My pleasure :smile:
     
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