Question: 1. a) what is the force per meter on a wire carrying a 9.80-A current when perpendicular to a 0.80-T magnetic field? b) What if the angle between the wire and the field is 45°?(adsbygoogle = window.adsbygoogle || []).push({});

For part a) I know that F = ILB, where I is the current, L is the length of the wire and B is the size of the magnetic field.

Therefore F = 9.80 x L x 0.80

= 7.84 x L

But how can you work out the force when you don’t know what L is?

For part b) I know that F = ILB sin θ

I’m not sure how to approach the problem other than what I have expressed. Any help you can offer will be great.....thanks :D

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# Homework Help: Magnetic fields and currents

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