Magnetic flux linkage and area as a vector

AI Thread Summary
A circular coil with a diameter of 24 mm and 40 turns is placed in a uniform magnetic field of 85 mT, leading to a calculated area of 4.5 x 10^-4 m² and a flux linkage of 1.53 mWb. When the coil is reversed in 95 ms, the change in flux linkage is 3.06 mWb, which accounts for the vector nature of area and the cosine function of the angle between the coil's normal and the magnetic field. The discussion highlights the importance of understanding that area is a vector, affecting the flux linkage as the coil rotates. The relationship between the angle and the change in flux linkage is explained through the formula BANcos(theta), indicating that the effective area exposed to the magnetic field changes as the coil rotates. Understanding this concept is crucial for solving similar problems in electromagnetism.
Jimmy Jazz
Messages
4
Reaction score
0

Homework Statement


A circular coil of diameter 24 mm has 40 turns. The coil is placed in a uniform magnetic field of flux density 85 mT with its plane perpendicular to the field lines.

a) i Calculate the area of the coil

ii The flux linkage through the coil.

b) The coil was reversed in a time of 95 ms.

Calculate

i the change of flux linkage through the coil.

ii the magnitude of the induced emf

Homework Equations


Flux linkage = NBA
EMF = rate of change of flux linkage

The Attempt at a Solution



Part a I am ok with ai) area = 4.5x10^-4 and flux linkage is BNA = 1.53 mWb
In part b I struggled to see why the answer was 3.06 mWb and not a change of 1.53 to zero as it rotated.
my logic being that it changes from 1.53 to zero as it rotated for the first 90 degrees then back to 1.53.

I remember reading area is a vector so if this is true does it mean the flux linkage is changing from 1.53 mWb to -1.53 mWb, This would give me the correct answer in the back of the textbook.

Is there anyway of seeing this without knowing that area is a vector as this is not in the textbook as a principle taught on my course.

Thanks you for any help
Jimmy
summary question.jpg
 
Physics news on Phys.org
I have just made the connection with my data sheet and the formula BANcos(theta)
Then the angle between a normal to the coil and the field with give the necessary change of sign on rotation through 180 degrees.
Is there any way of simply explaining why the area that the field lines cut changes as a cos function as the coil is rotated?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top