Magnetic Flux Through a Tilted Medium

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magnetpedro
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Imagine a ferromagnetic medium shaped as a cylinder (a ferromagnetic fiber) with a magnetic relative permeability of μr, tilted with an angle a, as shown in the picture.

220px-Cylinder_geometry.svg.png

I would like to prove analytically that the sum of the inductances measured along the x-axis (angle is a) and y-axis (angle is π/2 - a) is independent of the angle a. (Lsum = Lx + Ly independent of a).

Each case, Lx and Ly is also the sum of the inductance of the projections of the fiber in the x and y axis.
My approach consists in using Hopkinson's Law and first determining the Reluctance for each case, and then calculating the Inductance using L= N2/Reluctance, where N is a constant number of turns of a supposed magnetomotive force.

Do you think it's possible?

Thank you very much.
 
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marcusl said:
Don't understand your post. What is the inductance of a cylinder?

It's the Inductance of a ferromagnetic medium shaped as a cylinder, that is crossed by a flux produced by a magnetomotive force.
At least was this that I meant to say. Beg your pardon if I wasn't clear.
 
Inductance is a quantity that relates energy stored in a magnetic field to the currents producung the field. It also relates an induced emf to a changing current. You have no currents, hence no inductance.
 
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marcusl said:
Inductance is a quantity that relates energy stored in a magnetic field to the currents producung the field. It also relates an induced emf to a changing current. You have no currents, hence no inductance.

My mistake, forgot to mention that the magnetomotive force is produced by a current I (constant). That's my current.
 
Your problem doesn't make sense as stated and suggests that you don't understand inductance. Have you had an undergrad E&M course?
 
marcusl said:
Your problem doesn't make sense as stated and suggests that you don't understand inductance. Have you had an undergrad E&M course?

Yes I have. I'll try to explain this model.
Imagine that a magnetomotive force is produced by a number of turns N and a current I, being Fmm=N*I.
That magnetomotive force creates a magnetic flux ∅ that only crosses the ferromagnetic cylinder.
The inductance of the ferromagnetic medium/fiber can be determined using the following expressions:

L = N× ∅ / I

∅ = Fmm/R

L = N2/R

where R is the reluctance of the ferromagnetic medium, given by:

R= l/(μ0r*A)

where l is the length of the path of the magnetic flux, μ0 is the magnetic constant (vacuum's permeability), μr is the relative magnetic permeabilty of the ferromagnetic cylinder and A is the area that is crossed by the flux.
 
These formulas are usually written in terms of the number of turns per unit length n, in which case [itex]L=\frac{n^2l}{R}[/itex]. Furthermore, this applies to long solenoids. Since your core is short, this will be an approximation at best.

To your original question, however, inductance is a scalar quantity so you can't break it into x and y components.
 
marcusl said:
These formulas are usually written in terms of the number of turns per unit length n, in which case [itex]L=\frac{n^2l}{R}[/itex]. Furthermore, this applies to long solenoids. Since your core is short, this will be an approximation at best.

To your original question, however, inductance is a scalar quantity so you can't break it into x and y components.

Yes, inductance is a scalar quantity but I can make a projection of the ferromagnetic fiber along x and y, with a length and cross area also projected, calculate both Inductances Lx and Ly, and then the "final" inductance would be L = sqrt(Lx^2 + Ly^2).
 
Well yes, you could do that, but I don't see the value since L is already independent of your angle, by definition.
 
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