Magnetic Force, Electric Force

AI Thread Summary
A positively charged particle moving in the positive x direction through a uniform magnetic field in the positive z direction experiences a magnetic force in the negative y direction. To achieve a net force of zero, an electric field must be applied in the negative y direction, counteracting the magnetic force. The original poster believes the textbook answer of applying an electric field in the positive y direction is incorrect. The discussion highlights confusion over the direction of forces and the application of the right-hand rule. Ultimately, the consensus leans towards the need for an electric field in the negative y direction to balance the forces.
eprparadox
Messages
133
Reaction score
2

Homework Statement


24. A uniform magnetic field is in the positive z direction. A positively charged particle is moving in the positive x direction through the field. The net force on the particle can be made zero by applying an electric field in what direction?
A. Positive y
B. Negative y
C. Positive x
D. Negative x
E. Positive z


Homework Equations



F = q* (vxB)
F = q*E

The Attempt at a Solution



The answer for this problem is given and in my book it's given as B. However, I keep getting A. I don't know where I'm going wrong.

So if the positive particle is moving in the positive x-direction and the B-field is in the positive z direction, then the resulting magnetic force is in the negative y-direction. And if we want a net force of zero on this positive particle, then it seems like if we apply an electric field in the positive y direction then we could get the net zero force that we're looking for. Is this an incorrect explanation?
 
Physics news on Phys.org
I agree with you. I think the book is wrong. Anyone else?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top