Magnetic Force Exerted on Particle

AI Thread Summary
To find the magnetic force exerted on a charged particle moving in a magnetic field, the relevant equation is F = qvB, where F is the magnetic force, q is the charge, v is the velocity, and B is the magnetic field strength. The particle's velocity can be determined using the kinetic energy gained from the potential difference, calculated as KE = qV, leading to v = sqrt(2KE/m). Given the mass of 6.64e-27 kg, charge of +3.2e-19 C, and a potential difference of 2.45e6 V, the velocity is found to be approximately 1.55e7 m/s. Substituting these values into the magnetic force equation yields a force of 7.87e-12 N, confirming the provided answer. Understanding these principles is crucial for solving problems involving magnetic forces on charged particles.
moebiusatg
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Sorry for slightly disregarding the proper format but I'm really quite lost so I can abide by what is expected. However I will be detailed

Question is: A particle with a mass of 6.64e-27 kg and a charge of +3.2e-19 C is accelerated from rest through a potential difference of 2.45e6 V. The particle then enters a uniform 1.6-T magnetic field. If the particle's velocity if perpendicular to the magnetic field at all times, what is the magnitude of the magnetic force exerted on the particle?

I'm unsure how to start this problem but I know the answer is 7.87e-12 N.

Any help is greatly appreciated.

Thanks!
 
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Please include any relevant equations you are aware of. What is the formula for force exerted by a magnetic field?
 

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