- #1
Poop-Loops
- 732
- 1
Homework Statement
It's problem 2.b) on this page:
http://www.phys.washington.edu/users/schick/322A/322-08ps3.pdf
The Attempt at a Solution
So, what it looks like to me, since the only terms in the actual vector potential are all multiplied, Lambda would have to be a constant, so that when you take the gradient of it, it becomes 0 and doesn't change A'. So basically A=A' and Lambda = some constant vector.
If Lambda wasn't constant, then taking the gradient would give some additional terms added to A, whereas no addition takes place.