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Magnetic vector potential.

  1. Jan 23, 2008 #1
    1. The problem statement, all variables and given/known data

    It's problem 2.b) on this page:


    3. The attempt at a solution

    So, what it looks like to me, since the only terms in the actual vector potential are all multiplied, Lambda would have to be a constant, so that when you take the gradient of it, it becomes 0 and doesn't change A'. So basically A=A' and Lambda = some constant vector.

    If Lambda wasn't constant, then taking the gradient would give some additional terms added to A, whereas no addition takes place.
  2. jcsd
  3. Jan 24, 2008 #2


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    Write A' in Cartesian coords.
    Take the difference D=A-A'.
    It should be easy to show that D is a gradient.
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