Magnetism and Current Concept Query

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SUMMARY

The discussion centers on the relationship between magnetism and electric currents, specifically addressing the confusion surrounding the interaction of a current-carrying wire with an external magnetic field. The right-hand rule is established as a method for determining the direction of the magnetic field produced by a current. The force experienced by a wire in a magnetic field is described by the equation F = i.l.b.sin(x), where 'i' is the current, 'l' is the length of the wire, 'b' is the magnetic field strength, and 'x' is the angle between the wire and the magnetic field. The participant raises a valid point regarding the potential cancellation of the external magnetic field by the field produced by the wire itself.

PREREQUISITES
  • Understanding of electromagnetic theory
  • Familiarity with the right-hand rule for magnetic fields
  • Knowledge of the Lorentz force law, specifically F = qvB
  • Basic concepts of current-carrying conductors and magnetic fields
NEXT STEPS
  • Research the principles of superposition in magnetic fields
  • Study the implications of the Lorentz force on current-carrying wires
  • Explore the concept of magnetic field lines and their interactions
  • Learn about the applications of electromagnetism in engineering
USEFUL FOR

Students of physics, electrical engineers, and educators seeking to deepen their understanding of the interactions between electric currents and magnetic fields.

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Hi I'm currently reading up on magnetism and its relation to currents but there's one thing that frustrates me and the textbook doesn't seem to elaborate on it.

I understand that a current produces its own magnetic field (and we use the right-hand rule to determine this), it also makes sense that if we throw a particle into this current-created field, we can measure the force it feels via F = qvB. What's frustrating me is that in the next section, the textbook outlines how if we place a current-carrying wire on a magnetic field, the wire will feel a force of F = i.l.b.sin(x), but before it says that a current produces a magnetic field, so won't the magnetic field it produce partially cancel out the external magnetic field?
 
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The mag field produced by a wire does not produce a force on that wire.
 

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