Magnification at a Different Distance from Mirror?

AI Thread Summary
The discussion revolves around calculating magnification when a person moves further from a mirror. Initially, a magnification of 1.50 is achieved at a distance of 12.0 cm, with a focal length of 0.36 m. When the person moves to a distance of 3.7 times the focal length, the magnification becomes -0.62, indicating an inverted image. The conversation highlights confusion regarding the signs of magnification for real and virtual images, noting that real images are typically inverted while virtual images are upright. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement


The focal length between a person and his mirror that produces a magnification of 1.50 when his face is 12.0 cm away is 0.36 m. He then moves to a distance of 3.7 times the focal length away from her mirror. What is the magnification now?

Homework Equations


di/do=m
1/f=1/di+1/do

The Attempt at a Solution


I've been trying to work this out on paper for the last hour. When his distance is 2.6 times the focal length, the magnification is -0.62. I can't figure out why that is though. There seems to be 2 variables.
 
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