Magnitude & Direction of Magnetic Field

AI Thread Summary
An electron moving at 9.0 x 10^5 m/s in the positive y direction experiences no magnetic force, while moving in the positive z direction results in a force of 1.7 x 10^-13 N directed in the negative x direction. The magnetic field's magnitude and direction need to be determined using the equation B = F/(|q|vsinθ). The user initially assumed a 90-degree angle between the velocity and magnetic field vectors but received incorrect results for both the magnitude and direction. It is suggested to reconsider the sign of the electron's charge and the angle used in calculations for accurate results.
yayirunin2car
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Homework Statement


An electron moving with a speed of 9.0 multiplied by 105 m/s in the positive y direction experiences zero magnetic force. When it moves in the positive z direction it experiences a force of 1.7 multiplied by 10-13 N that points in the negative x direction. What is the magnitude and direction of the magnetic field?


Homework Equations


B = F/(|q|vsinθ)


The Attempt at a Solution


I plugged in the force, the velocity, the charge as 1.60e-19, and guessed that the angle was 90 degrees between the velocity and magnetic field vectors. My answer was wrong, and my guess of the direction of the magnetic field in the positive y direction was also wrong. So, I'm hoping it's in the negative y direction.

Any help?

Thanks in advance!
 
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yayirunin2car said:
I plugged in the force, the velocity, the charge as 1.60e-19, and guessed that the angle was 90 degrees between the velocity and magnetic field vectors. My answer was wrong, and my guess of the direction of the magnetic field in the positive y direction was also wrong. So, I'm hoping it's in the negative y direction.
Details of the calculation are not shown. So, it is difficult to identify the mistake. Be sure to take into account the sign of the charge of the electron.
 
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