Magnitude of Acceleration given a pendulum equilibrium

AI Thread Summary
The discussion revolves around calculating the magnitude of acceleration for a pendulum in a jet plane that shifts its equilibrium position during uniform acceleration. The pendulum's length is 1.36m, and the new equilibrium position is 0.410m from the vertical. A user initially attempted to find the angle of swing using geometric methods but miscalculated the resulting acceleration as 169.9 m/s². Clarifications were made regarding the definition of "equilibrium," emphasizing that it refers to the pendulum's position when stationary, not at the extremes of its swing. The conversation highlights the importance of accurately interpreting the problem's terms to solve for the plane's acceleration correctly.
joejoemickgo
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Homework Statement



A pendulum has a length L = 1.36m. It hangs straight down in a jet plane about to take off as shown by the dotted line in the figure. The jet then accelerates uniformly, and while the plane is accelerating, the equilibrium position of the pendulum shifts to the position shown by the solid line, with D = 0.410m. Calculate the magnitude of the plane's acceleration.

http://capa-new.colorado.edu/msuphysicslib/Graphics/Gtype09/prob48_sidepend.gif


Homework Equations





The Attempt at a Solution


I have attempted this many ways. First of all I found the angle that the pendulum swung by using the length of the pendulum rope as two sides of an isosceles triangle. Then placing D = .410 m at the base of this triangle. Then splitting the triangle in half, creating two right triangles. Solving for the top angle and timesing it by two to get the angle of the pendulum swing. I then used gravity, 9.8 m/s/s and found an acceleration of 169.9 m/s/s but this was wrong. I have no idea anymore... anything would help.
 
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hi joejoemickgo! welcome to pf! :smile:
joejoemickgo said:
… The jet then accelerates uniformly, and while the plane is accelerating, the equilibrium position of the pendulum shifts to the position shown by the solid line, with D = 0.410m.

First of all I found the angle that the pendulum swung by using the length of the pendulum rope as two sides of an isosceles triangle. Then placing D = .410 m at the base of this triangle. Then splitting the triangle in half, creating two right triangles. Solving for the top angle and timesing it by two to get the angle of the pendulum swing. I then used gravity, 9.8 m/s/s and found an acceleration of 169.9 m/s/s but this was wrong. I have no idea anymore... anything would help.

ah, nooo :redface: … "equilibrium" means when the pendulum is in the middle of the swing (zero angular acceleration, maximum angular speed), not when it's stationary at the ends of the swing

"equilibrium" refers to the position at which the pendulum would remain stationary if you held it there and then let go :biggrin:
 
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