Magnitude of acceleration given the orbit

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The discussion revolves around calculating the acceleration due to gravity for a satellite in a circular orbit 3.22 × 10^5 m above Earth's surface. The relevant formula used is a = MG/R^2, where M represents the mass of the Earth, not the satellite. Participants clarify that the radius in the equation must be squared, which is crucial for accurate calculations. The confusion about the mass of the satellite is resolved, confirming that only the Earth's mass is needed for this calculation. The final understanding emphasizes the importance of correctly applying the formula to determine gravitational acceleration at the specified altitude.
Shadow236
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Homework Statement


A satellites are placed in a circular orbit that is 3.22 × 105 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

Homework Equations


a = MG/R^2

The Attempt at a Solution


For the above formula I have trouble because I do not know the mass of the satellite. I end up with

a = M (6.67 x 10^-11)/(6.38 x 10^6 + 3.22 x 10^5)^2
 
Last edited:
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Shadow236 said:

Homework Statement


A satellites are placed in a circular orbit that is 3.22 × 105 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?


Homework Equations


a = MG/R^2


The Attempt at a Solution


For the above formula I have trouble because I do not know the mass of the satellite. I end up with

a = M (6.67 x 10^-11)/(6.38 x 10^6 + 3.22 x 10^5)

Which mass does the M in your Relevant Equation represent?

Also, be sure to not forget that the radius in the denominator must be squared.
 
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Does it represent the mass of the earth?

EDIT: It does represent the mass of the Earth. Thank you!
 
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